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Automotive Material UNIT-1 (3 Marks)

3 marks Questions:
1.  Explain  the  working  principle  of  magnetic  particle  inspection  testing.
A. MAGNETIC PARTICLE INSPECTION
Magnetic particle method is used for locating surface and subsurface dis- continuities in Ferro-magnetic materials. It is based on the fact that. when the material or the part under test is magnetized, magnetic discontinuities that lie in a direction generally transverse to the direction of the magnetic field, will cause a leakage field to be formed at and above the surface of the part. The presence of this leakage field, and therefore the presence of the discontinuity, is detected by the use of finely divided Ferro-magnetic part1- clues applied over the surface, some of the particles being gathered and held by the leakage field. This magnetically held collection of particles forms an outline of the discontinuity and generally indicates its location, size, shape and extent. Magnetic particles are applied over a surface as dry particles, or as wet particles in a liquid carrier such as water or oil.

 One of the basic requirements of magnetic particle inspection is that the part undergoing inspection must be properly magnetized, so that leakage fields created by discontinuities will attract the magnetic particles. Ferro- magnetic materials can be magnetized in two different ways, either, by the use of permanent magnets, or by passing an electric current through the material.
A horse shoe magnet can be used to magnetize the material to be tested. The principle of working of a horse shoe magnet is explained in the Fig..When a magnetic material is placed across the poles of a horse shoe magnet having square ends, forming a closed or ring-like assembly,
the magnetic lines of force flow from the north pole through the magnetic material to the south pole and are entirely enclosed Within the ring-like assembly, because no external poles exist. As a result. any iron fillings or magnetic particles dusted over this assembly are not attracted to the magnet. But if one end of the magnet is not square, an air gap exists between that end of the magnet and the magnetic material. The poles (of the shoe-magnet) will than attract magnetic materials and the magnetic particles will cling-to the poles and bridge the gap between them. Similarly any radial crack in a circularly magnetized piece will create a north and a south magnetic pole at the edges of a crack. Magnetic particles will be attracted to the poles created by such a crack, giving an indication of the discontinuity in the piece.

When the magnetic flux is produced in a ferromagnetic material by pas- sing an electric current through a coil of wire wound around the material, the method is called Iiiagra flux inspection. Production of leakage field at the crack in a cylindrical bar by passing current through a solenoid coil is shown in Fig(b).
 
2.  What is  crystal imperfection?  Enlist  the types  of  imperfection  in crystal structure? 
A.CRYSTAL IMPERFFCTION
 Real crystals deviate from the perfect periodicity of atoms Which is assumed in an ideal crystal. This deviation is chiefly responsible for the changes in the mechanical and electrical properties of the real crystals. This deviation of atoms from an orderly array of lattice points is termed as defect or imperfection. An understanding of these lattice defects is very important to explain the mechanical behaviour of metals. For example the actual strength- th of polycrystalline material is about 10 3 to 10 5 times lower than the theoretical strength of an ideal crystal.

Crystal defects or imperfections could be of three types—
point defects
line defects
area defects.
3.  What is  the difference  between slip  and  twin?
A.

4.  Explain  working  principle  of  ultra-sonic  testing.
A. Ultrasonic inspection is a non-destructive method in which beams of high-frequency sound waves are introduced into the material being inspected. The sound waves travel through the material with some attendant loss of energy and are reflected at interfaces. The reflected beam is detected and analyzed to define the presence and location of flaws.
 Ultrasonic inspection employs ultrasonic waves. These waves are mechanical waves (in contrast to light or x-rays) that consist of oscillations or vibrations of the atomic or molecular particles of a substance. Ultrasonic wave behave essentially in the same way as audible sound waves. Most ultrasonic inspection is done at frequencies between 1 to 25 megacycles, well above the audible or sonic range, which is about 20 cycles to 20 kilo- cycles per second The directivity of ultrasonic vibrations increases with an increase in their frequency. At a frequency, of the order of one megacycle  per second, the angle of divergence is so small that they may be called ‘ultrasonic beams".

5.  Explain  working  principle  of Radiography  testing.
A.RADIOGRAPHIC INSPECTION :
Radiography is based on the fact that when highly penetrating rays, such as x-rays, are passed through a metal object, they are partly absorbed by the metal. The degree of absorption of the x-rays through the metal varies, depending upon the lack of homogeneity of material in different areas in. the metal. Areas having defects, such as blowholes and cracks, metal would absorb less x-rays than the remaining areas. This varying degree of absorption of x-rays can be determined by placing a sensitive photographic film on the other side of the specimen.
The photographic film. is darkened differently at different places depending upon the position of the defects in the metal. Regions more penetrable to x-rays radiation will be darker and the areas of high absorption will be lighter. Production of such a radiograph is shown in Fig. 16.3.

The penetration power of x-rays depends upon the wavelength of the
rays. which mainly varies from 10 to 0.1 Angstrom. The lower the wave-
length. the more penetrating the rays. Generally, these x-rays can pass through steel specimens up to 100 mm thick, copper and its alloys up to 60 mm thick and aluminium and its alloys up to 400 mm thick.
  

3 marks Questions:


6.  Explain  the  Bragg’s law  of  X-ray  diffraction  in detail with  neat  sketch.
A.
       The crystal an diffract x ray because the inter planner spacing in crystal lattice is of some order as that of wavelength of x ray.
       Diffraction: It is a bending of line around the corner and it depend on wavelength.
       Diffraction due to inter planner spacing.
       separation of layer= x RAY wavelength.
       X-ray transmitted to words the crystal lattice. And this Xray are reflected and detected by detector
       Ray 2 travel more distance then ray one.
       Extra difference is DE+EF then if ray 2 and ray 1 have a same of phase after reflection thus path difference  is decide if both are in same phase or not.
The different layers of crystal
      

7.  What are  the  basic  processing  steps  of a  liquid  penetrant  inspection?
A. Steps of  Liquid  Penetrant Testing : The  general steps can  be  summarized  as follows:
 1. Surface  Preparation : ). One  of  the  most  critical  steps  of  a  liquid a person  with  a penetrant  testing  is the surface  preparation.  The  surface  must  be  free  of  oil,  grease,  water,  or  other  contaminants that  may  prevent  Penetrant  from  entering  flaws.  The  sample  may  also  require  etching  if mechanical  operations  such  as  machining,  sanding,  or grit  blasting  have  been  performed. These  and  other  mechanical operations can  smear  metal over  the  flaw  opening  and prevent the penetrant  from entering.
2. Penetrant  Application : penetrant  material Once  the  surface  has  been  thoroughly  cleaned  and  dried, the is  applied  by  spraying,  brushing,  or  immersing  the  part  in  a  penetrant bath.
3. Penetrant  Dwell : The  penetrant  is  left  on  the  surface  for  a sufficient  time allow  as much  penetrant  as  possible  to  be  drawn  from  or  to  seep  into  a  defect.  Penetrant  dwell  time is  the  total with  the times  are by to time  that  the  penetrant  is  in  contact part surface. usually the required being dwell from  five Dwell recommended penetrant  producers  or by  the specification followed. Minimum times  typically  range to 60 minutes. 4. Excess  Penetrant  Removal : This  is  the  most  delicate  part  of  the  inspection procedure because  the  excess  penetrant  must  be  removed  from  the  surface  of  the  sample  while removing  as  little  penetrant  as  possible  from  defects.  Depending  on  the  penetrant  system used,  this  step  may  involve  cleaning  with  a  solvent,  direct  rinsing  with  water,  or  first treating  the  part with an  emulsifier  and then rinsing  with water
5. Developer  Application : A  thin  layer  of  developer  is  then  applied  to  the  sample  to penetrant  trapped  in  flaws  back  to  the  surface  where  it  will  be  visible. draw Developers  come in  a  variety  of  forms  that  may  be  applied  by  dusting  ( ( dry powders wet developers ). ), dipping,  or  spraying
6. Indication  Development : period The  developer Photo  Courtesy  of  Contoso is allowed to stand on the  part surface  for  a of time  sufficient to permit the  extraction of  the trapped penetrant out  of any surface  flaws. This development time is usually  a  minimum of 10 minutes. Significantly  longer  times may  be  necessary  for  tight cracks.
7. Inspection :  Inspection  is  then  performed from any  flaws  which may  be  present.
8. Clean  Surface : under appropriate  lighting The  final step in the  process is to thoroughly  clean the part surface  to remove the developer  from the  parts that were  found  to be acceptable. to  detect indications
8.  Differentiate  between  substitutional  and  interstitial solid  solution.
A.
Substitutional solid solution
Interstitial solid solution
Substitutional Solid Solution  is formed when some of the atoms of solvent are replaced by the solute atoms at their normal lattice points, as shown in Fig.. In the formation of substitutional solid solutions, an element A cannnot dissolve any amount of element B, its limit (known as solid solubility limit) is determined by certain factors. These factors were first studied by Hume Rothery and are
known as Hume Rothery Rules.

 interstitial solid solution is formed when
atoms of small atomic radii fit into the empty spaces or interstices of the lattice structure of the solvent atoms as shown in Fig.. Since the empty spaces of the lattice structure are limited in size, only atoms with atomic radii less than I angstrom are likely to form interstitial solid solu-tions.

 Interstitial solid solutiom normally have limited solid solubility. The
well known example of this group is interstitial solid solution of carbon in iron. y-iron can dissolve uptu 2 per cent carbon at 1147 'C. This interstitial solid solution Of carbon in iron is the basis for hardening in steel.
Interstitial solid solution ot hydrogen in min formed during acid pickling (cleaning), plating or welding operations With steel causes a sharp decrease in ductility of steel. This harmful phenomenon is known as hydrogen embritllemem.


 



9.  Write  difference  between crystalline  solid  and  non-crystalline  solid.
A. Crystalline Solids: Crystalline Solids have an evenly distributed three-dimensional arrangement of atoms, ions, or molecules.
 Non-crystalline solids: Non-crystalline solids do not have a consistent arrangement of particles.
 Properties of Crystalline and Non-crystalline Solids
 Geometrical Shape
 Crystalline Solids: Crystalline solids have a well-defined geometrical shape due to the regular arrangement of unit cells.
 Non-crystalline Solids: Non-crystalline solids do not have well-defined geometrical shape.
 Range Order

 Crystalline Solids: Crystalline solids have a long range order.
 Non-crystalline Solids: Non-crystalline solids have a short range order.
 Melting Point
 Crystalline Solids: Crystalline solids have a definite melting point.
 Non-crystalline Solids: Non-crystalline solids melt over a range.
 Heat of Fusion
 Crystalline Solids: Crystalline solids have a high fixed value for the heat of fusion.
 Non-crystalline Solids: Non-crystalline solids do not have a fixed value for the heat of fusion.
 Properties of Solids
 Crystalline Solids: Crystalline solids are true solids. They show all the properties of solids.
 Non-crystalline Solids: Non-crystalline solids do not show all the properties of solids. Therefore, they are called “pseudo solids”.
 Energy
 Crystalline Solids: Energy in crystalline solids is lower than that of non-crystalline solids.
 Non-crystalline Solids: Nature favours crystalline solids due to the low energy arrangement.
10.  State  different  types  of  unit cells  and  sketch their geometries.
A.• The four basic  types  of unit  cells  are : 
Simple
Body Centred cubic
Face centred cubic
Base centred cubic
Hexagonal Closed packed


11.  What is meant by  ‘ Bravai’s  Lattice ’?  Write the  names  of seven  crystal system.
A. In geometry and crystallography, a Bravai’s lattice is an infinite array of discrete points in three dimensional space generated by a set of discrete translation operations described by:
When the discrete points are atoms, ions, or polymer strings of solid matter, the Bravais lattice concept is used to formally define a crystalline arrangement and its (finite) frontiers. A crystal is made up of a periodic arrangement of one or more atoms (the basis) repeated at each lattice point. Consequently, the crystal looks the same when viewed from any equivalent lattice point, namely those separated by the translation of one unit cell (the motif).
 

12.  Define  space  lattice. What  are the  characteristics of  a  space  Lattice?
A. A crystalline substance is one which is made of crystals or parts of crystals. In a crystal,  the atoms are arranged in a periodic and regular geometric pattern in space. The arrangement of atoms in a crystal can be described with respect to three dimensional net of straight lines, called a space Lattice.


13.  Explain  with neat  sketches  the arrangement  of  atoms in  B.C.C,
F.C.C  and  H.C.P  Lattice.
A.
BCC
FCC
HCP

14.  Explain  simple  cubic crystal structure  with  neat  sketch.
A.
15.  Draw  the cubic  crystal planes  for following  Miller  indices:
(i)  (0  1  0)     (ii)  (0  0  1)     (iii)  (1  2  0). 
A. 



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